Sbcl5 g →sbcl3 g +cl2 g
WebA) SbCl5 (g)-->SbCl3 (g)+Cl2 (g) Express your answers as signed integers. Enter the initial and the final oxidation states separated by a comma. Sb: Express your answers as signed... WebChemistry 1 answer 1 watching 272 views 27 Nov 2024 Antimony pentachloride decomposes according to the equation SbCl5 (g) <------> SbCl3 (g) + Cl2 (g) Suppose that the initial concentrations are [SbCl5]0 = 0.165 M, [SbCl3]0 = 0.0955 M, and [Cl2]0 = 0.210 M.
Sbcl5 g →sbcl3 g +cl2 g
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WebJan 15, 2011 · At elevated temperatures, SbCl5 gas decomposes into SbCl3 gas and Cl2 gas as shown by the following equation: SbCl5 (g)<=> SbCl3 (g) + Cl2 (g) (a) An 59.8 gram sample of SbCl5 (molecular weight 299.0) is placed in … WebApr 1, 2024 · Antimony pentachloride decomposes according to this equation: SbCl5 (g) ⇌ SbCl3 (g) + Cl2 (g) An equilibrium mixture in a 5.00-L flask at 448 °C contains 3.85 g of …
WebMar 5, 2024 · Calculate ΔH° for the process Sb (s) + 52Cl2 (g) → SbCl5 (s) from the following information: Sb (s) + 32Cl2 (g) → SbCl3 (s) ΔH° = −314 kJ SbCl3 (s) + Cl2 (g) → SbCl5 (s) ΔH° =... Web(完整版)第二章补充习题及答案普通化学_试卷_化学
Web2024版新高考版化学总复习专题十七实验方案的设计与评价专题检测.docx,北京曲一线图书策划有限公司 2024版《5年高考3年模拟》A版 第 第 PAGE 6 页 共 NUMPAGES 6 页 专题十七 实验方案的设计与评价 1.下列实验装置不能达到实验目的的是( ) A.测定乙醇结构 B.制取少量CO2 C.制取少量碳酸钙 D.提纯乙酸乙酯 ...
WebMar 20, 2015 · At elevated temperatures, SbCl5 gas decomposes into SbCl3 gas and Cl2 gas as shown by the following equation: SbCl5(g)<=> SbCl3(g) + Cl2(g) (a) An 59.8 gram sample of SbCl5 (molecular weight 299.0) is placed in an evacuated 15.0 liter container at 182°C. Determine the value of the equilibrium constant (Kp) at 800. K and 1 atm pressure.
WebScience. Chemistry. Chemistry questions and answers. A)SbCl5 (g)→SbCl3 (g)+Cl2 (g) Express your answers as signed integers. Enter the initial and the final oxidation states … my route 使ってみたa) An 89.7-gram sample of SbCl5 (molecular weight 299.0) is placed in an evacuated 15.0-liter container at 182 °C. my round the baysWebScience Chemistry Calculate ΔH°298 for the processSb (s) + (5)/ (2)Cl2 (g) SbCl5 (g)from the following information:Sb (s) + (3)/ (2)Cl2 (g) SbCl3 (g) ΔH°298 = −314 kJSbCl3 (s) + … the shakespeare newport shropshireWebThis new fourth edition of General Chemistry takes an atoms-first approach from beginning to end. In the tradition of McQuarrie s many previous works, it promisesto be another ground-breaking text. This superb new book combines the clear writing and wonderful problems that have made McQuarrie famous among chemistry professors and students ... the shakespeare oxford newsletterWebQuestion Calculate Δ H ° 298 for the process Sb ( s) + (5)/ (2)Cl 2 ( g) SbCl 5 ( g) from the following information: Sb ( s) + (3)/ (2)Cl 2 ( g ) SbCl 3 ( g ) Δ H ° 298 = −314 kJ SbCl 3 ( s) + Cl 2 ( g ) SbCl 5 ( g ) Δ H ° 298 = −80 kJ Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution star_border the shakespeare inn welford on avonWebFor the reaction SbCl5(g) SbCl3(g) + Cl2(g), (SbCl5) = -334.34 kJ/mol (SbCl3) = -301.25 kJ/mol (SbCl5) = -394.34 kJ/mol (SbCl3) = -313.80 kJ/mol Will this reaction proceed spontaneously at 298 K and 1 atm pressure? 9. my route mspfWebCreate an equation for each element (Sb, Cl) where each term represents the number of atoms of the element in each reactant or product. Sb: 1a + 0b = 1c Cl: 0a + 2b = 3c Solve For All Variables Use substitution, Gaussian elimination, or a calculator to solve for each variable. Using Substitution or Elimination Using Linear Systems / Algebra the shakespeare pub telford